Help me identify the coordinates of the center of this ellipse. (x-2)^2/36+(y+1)^2/25=1

Question

jdoe0001 · Answer

$\bf\cfrac{(x-h)^2}{a^2}+\cfrac{(y-k)^2}{b^2}=1\
\textit{center is at coordinates }(h,k)$

anonymous · Answer

$$\frac{(x-\color{red}h)^2}{a^2}+\frac{(y-\color{blue}k)^2}{b^2}=1$$ \
$$\frac{(x-\color{red}2)^2}{a^2}+\frac{(y-\color{blue}{(-1}))^2}{b^2}=1$$

anonymous · Answer

center is $(\color{red}h,\color{blue}k)$

anonymous · Answer

therefore the coordinates are (2,1) , correct?

anonymous · Answer

sorry (-2,1)

jdoe0001 · Answer

$\bf \cfrac{(x-\large{\color{red}2})^2}{a^2}+\cfrac{(y-\color{blue}{(\large{-1}}))^2}{b^2}=1$   look closely

jdoe0001 · Answer

$\bf \cfrac{(x-h)^2}{a^2}+\cfrac{(y-k)^2}{b^2}=1$

anonymous · Answer

ok so would it be (2,-1) ?

jdoe0001 · Answer

yeap, the " - " in the equation, isn't part of the "h" or the "k", so yes, 2, -1

anonymous · Answer

thanks!

jdoe0001 · Answer

yw