lim 0 goes to theta of sin(3 theta)/(theta)
Welcome to Openstudy! This is the question right? \[\lim_{x \rightarrow 0} \frac{\sin \theta}{\theta}\]
Yes!
lim theta goes to 0
\[\lim_{\theta \rightarrow 0} \frac{\sin 3 \theta}{\theta}\]
Yeah that's the question
theta is measured in radians
@SithsAndGiggles This is simple for you
I must estimate the limit
Recall that \[\lim_{\theta\to0}\frac{\sin a\theta}{a\theta}=1\] How can you get a 3 in the denominator without fundamentally altering the function?
I'm not sure
Well if you were to multiply by 1, you'd have the same thing right? Fortunately for use, \(\dfrac{3}{3}=1\), so \[\frac{\sin3\theta}{\theta}=\frac{\sin3\theta}{\theta}\cdot\frac{3}{3}\]
I have that...not sure where to go from there
Then you also have \[3\lim_{\theta\to0}\frac{\sin3\theta}{3\theta}\]
What's the next step?
See the previous comment: \(\color{blue}{\text{Originally Posted by}}\) @SithsAndGiggles Recall that \[\lim_{\theta\to0}\frac{\sin a\theta}{a\theta}=1\] \(\color{blue}{\text{End of Quote}}\)
Got it, the answer is 3
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