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Chemistry 20 Online
OpenStudy (toxicsugar22):

In the explosion of a hydrogen-filled balloon, 0.90g of hydrogen reacted with 7.2g of oxygen. How many grams of water vapor are formed? (Water vapor is the only product.)

thomaster (thomaster):

what is the reaction equation?

thomaster (thomaster):

what?

thomaster (thomaster):

Do you even know what a reaction equation is?

thomaster (thomaster):

No, the product is water

thomaster (thomaster):

A reaction equation is something like this: \(\sf\large reactant\ 1+reactant\ 2\to product\)

thomaster (thomaster):

Can't say the person who helped you with your previous question did a good job.

thomaster (thomaster):

\(\sf\large hydogen+oxygen\to water\)

OpenStudy (toxicsugar22):

ok

OpenStudy (toxicsugar22):

i get that know

thomaster (thomaster):

Do you know the chemical formulas for hydrogen, oxygen and water?

OpenStudy (toxicsugar22):

yes

thomaster (thomaster):

So what are they?

OpenStudy (toxicsugar22):

no wait i am stuck

OpenStudy (toxicsugar22):

can you tell me and ill take notes

OpenStudy (toxicsugar22):

plesase

thomaster (thomaster):

Hydrogen = \(\sf H_2\) Oxygen = \(\sf O_2\) Water = \(\sf H_2O\) put those in the equation and you'll get: \(\sf H_2+O_2\to H_2O\) Now we have to balance the equation so that there are an equal amount of H's and O's on both sides of the arrow. Any idea how to do that?

thomaster (thomaster):

No. On the left there are 2 O's and on the right there is only 1 O

OpenStudy (toxicsugar22):

OK

thomaster (thomaster):

How about the H's?

OpenStudy (toxicsugar22):

1 ON BOTH SIDE

thomaster (thomaster):

no, 2 on both sides

OpenStudy (toxicsugar22):

NO SRRY YES THAT IS WHAT I MEANT

thomaster (thomaster):

So the problem is the Oxygen. how about we add a 2 before hydrogen \(\sf H_2+O_2\to 2H_2O\) is everything right now?

OpenStudy (toxicsugar22):

yes

OpenStudy (toxicsugar22):

im not lost

thomaster (thomaster):

Count the O's on the left and on the right. Are they the same? Then do the same for the H's

OpenStudy (toxicsugar22):

yes

thomaster (thomaster):

So how many O's and H's are on both sides? I need you to show some effort, I'm not here to give you the answer. You're here because you want to learn how to do this right? Or do you only want the answer?

OpenStudy (toxicsugar22):

there are two hydrogen and oxygen in both sisdes

thomaster (thomaster):

2H2O means 2 times H2 which is 4 H's

thomaster (thomaster):

So we have the oxygen equal. the hydrogen is 2 on the left, 4 on the right. how do we fix that?

OpenStudy (toxicsugar22):

put the rigt to the left

thomaster (thomaster):

no

OpenStudy (toxicsugar22):

bring the 4 hydroge on the righ and put it in front of the oxygen

OpenStudy (toxicsugar22):

how do we do that

thomaster (thomaster):

we add a coefficient before the H2 on the left side. 1x H2 = 2 H's 2x H2 = 4 H's So the coefficient is 2. Simply put a 2 before H2 on the left side so the equation will be: \(\sf 2H_2+O_2\to 2H_2O\) Now there are 4 H's and 2 O's on both sides which means the equation is "balanced"

OpenStudy (toxicsugar22):

ok

OpenStudy (toxicsugar22):

makes sense

OpenStudy (toxicsugar22):

now what next

thomaster (thomaster):

Now that we know the reaction equation, the next step is converting the amounts of reactants to moles. Any idea how to convert 0.90 gram hydrogen to mol hydrogen?

OpenStudy (toxicsugar22):

is it 0.8929102922793023

OpenStudy (toxicsugar22):

if no then i dont

OpenStudy (toxicsugar22):

if that not right

thomaster (thomaster):

To convert grams to mole. you have to divide by the molar weight of hydrogen. what is the molar weight of hydrogen? you can find it on a periodic table like http://ptable.com

OpenStudy (toxicsugar22):

1.01

thomaster (thomaster):

show your work

OpenStudy (toxicsugar22):

1.01 is the moler weight of hydrogen

OpenStudy (toxicsugar22):

that all i can do

thomaster (thomaster):

the molar weight of hydrogen is 1.008 gram/mol now divide the mass of hydrogen by 1.008 to get the amount of moles

OpenStudy (toxicsugar22):

.8928571428571429

OpenStudy (toxicsugar22):

right

thomaster (thomaster):

But we don't have H, we have H2. So the molar weight is not 1.008 but 2.016

OpenStudy (toxicsugar22):

0.4464285714285714

OpenStudy (toxicsugar22):

right

thomaster (thomaster):

right. Now do the same for oxygen

OpenStudy (toxicsugar22):

oxygen moar weight is 15.9994 right

thomaster (thomaster):

yes that's the molar mass of an oxygen atom, so what's the molar weight of an oxygen molecule?

OpenStudy (toxicsugar22):

7.2 g

thomaster (thomaster):

Oxygen atom = O Oxygen molecule = O2 just 2*15.9994

OpenStudy (toxicsugar22):

31.9988

thomaster (thomaster):

Yes 31.9988 gram/mol. now we have 7.2 gram oxygen molecules how many moles is that?

OpenStudy (toxicsugar22):

0.2250084378164181

OpenStudy (toxicsugar22):

right

thomaster (thomaster):

Yes So we have 0.446 mol H2 and 0.225 mol O2 The ratio of the equation is: 2:1->2 2 mol H2 reacts with 1 mol O2 to produce 2 mol H2O Now we have to find the limiting reactant. This is the reactant that determines how much of the other (excessive) reactant is used in this reaction. The limiting reactant is fully used. Which of the reactants is the limiting reactant?

OpenStudy (toxicsugar22):

is it oxygen

thomaster (thomaster):

Yes. we only have 0.22 mol oxygen and in the ratio only 1 mol oxygen is used and 2 mol hydrogen. which means we need the double amount in mol hydrogen (which is 2x0.22 = 0.44) This is exactly the amount of moles hydrogen we have so both reactants are fully used. Now we calculate how many moles H2O we get from this reaction. we do this by taking the limiting reactant (oxygen) and the ratio of the limiting reactant and the product. This ratio is 1:2 1 mol oxygen is used to produce 2 mol water vapor but we only have 0.22 mol oxygen. how many mol water vapor can we produce with that?

OpenStudy (toxicsugar22):

i dont know that

thomaster (thomaster):

1 mol oxygen = 2 mol water vapor 0.22 mol oxygen = ? mol water vapor

OpenStudy (toxicsugar22):

3 i guess

thomaster (thomaster):

Well that's a very strange guess. The only think you have to do is multiply it by 2

OpenStudy (toxicsugar22):

.44 srry

thomaster (thomaster):

Yes, now the last step is to convert 0.44 mol H2O to grams any ideas?

OpenStudy (toxicsugar22):

give me steps

thomaster (thomaster):

Just the reverse of what we did to convert grams to moles. multiply by molar mass. what is the molar mass of H2O?

OpenStudy (toxicsugar22):

2.0158

thomaster (thomaster):

how is that possible? the mass of 1 oxygen atom is already 16 gram/mol

OpenStudy (toxicsugar22):

correct me please

thomaster (thomaster):

Do determine the molar mass of a compount, just break it into pieces. We can break H2O in 2 pieces. 2x H and 1x O just take the molar mass of H and multiply it with 2 then take the molar mass of O and add it to the H's

OpenStudy (toxicsugar22):

ok

OpenStudy (toxicsugar22):

so hydrogen is 2.01588 when multiplied by two and the moler mass of oxygen is 31.9988

thomaster (thomaster):

hydrogen is 1.008 we're talking about atoms here. not molecules so only 1 H

thomaster (thomaster):

2* H= 2*1.008 = 2.016 1* O= 1*15.9994= 15.9994 ------+

OpenStudy (toxicsugar22):

i will understand this if you jusr do it and then explain after the problem

thomaster (thomaster):

just add 2.016 and 15.9994...

OpenStudy (toxicsugar22):

18.01

OpenStudy (toxicsugar22):

right

thomaster (thomaster):

Yes. now multiply that with the amount of moles H2O we have and you'll have the answer

OpenStudy (toxicsugar22):

again how much h20 moles

thomaster (thomaster):

we just calculated that, are you even trying to understand this? scroll back up to see it

OpenStudy (toxicsugar22):

yes

OpenStudy (toxicsugar22):

2.01588

OpenStudy (toxicsugar22):

is that the mole

thomaster (thomaster):

no... 0.22 gram/mol

OpenStudy (toxicsugar22):

of h20

OpenStudy (toxicsugar22):

0.22 is the mole

thomaster (thomaster):

yes but we have 2 mol h2o in the equation right? So that would be 0.44 mol H2O Now just multiply that with the molar mass of water to get the grams

OpenStudy (toxicsugar22):

7.9244

OpenStudy (toxicsugar22):

right

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