In the explosion of a hydrogen-filled balloon, 0.90g of hydrogen reacted with 7.2g of oxygen. How many grams of water vapor are formed? (Water vapor is the only product.)
what is the reaction equation?
what?
Do you even know what a reaction equation is?
No, the product is water
A reaction equation is something like this: \(\sf\large reactant\ 1+reactant\ 2\to product\)
Can't say the person who helped you with your previous question did a good job.
\(\sf\large hydogen+oxygen\to water\)
ok
i get that know
Do you know the chemical formulas for hydrogen, oxygen and water?
yes
So what are they?
no wait i am stuck
can you tell me and ill take notes
plesase
Hydrogen = \(\sf H_2\) Oxygen = \(\sf O_2\) Water = \(\sf H_2O\) put those in the equation and you'll get: \(\sf H_2+O_2\to H_2O\) Now we have to balance the equation so that there are an equal amount of H's and O's on both sides of the arrow. Any idea how to do that?
No. On the left there are 2 O's and on the right there is only 1 O
OK
How about the H's?
1 ON BOTH SIDE
no, 2 on both sides
NO SRRY YES THAT IS WHAT I MEANT
So the problem is the Oxygen. how about we add a 2 before hydrogen \(\sf H_2+O_2\to 2H_2O\) is everything right now?
yes
im not lost
Count the O's on the left and on the right. Are they the same? Then do the same for the H's
yes
So how many O's and H's are on both sides? I need you to show some effort, I'm not here to give you the answer. You're here because you want to learn how to do this right? Or do you only want the answer?
there are two hydrogen and oxygen in both sisdes
2H2O means 2 times H2 which is 4 H's
So we have the oxygen equal. the hydrogen is 2 on the left, 4 on the right. how do we fix that?
put the rigt to the left
no
bring the 4 hydroge on the righ and put it in front of the oxygen
how do we do that
we add a coefficient before the H2 on the left side. 1x H2 = 2 H's 2x H2 = 4 H's So the coefficient is 2. Simply put a 2 before H2 on the left side so the equation will be: \(\sf 2H_2+O_2\to 2H_2O\) Now there are 4 H's and 2 O's on both sides which means the equation is "balanced"
ok
makes sense
now what next
Now that we know the reaction equation, the next step is converting the amounts of reactants to moles. Any idea how to convert 0.90 gram hydrogen to mol hydrogen?
is it 0.8929102922793023
if no then i dont
if that not right
To convert grams to mole. you have to divide by the molar weight of hydrogen. what is the molar weight of hydrogen? you can find it on a periodic table like http://ptable.com
1.01
show your work
1.01 is the moler weight of hydrogen
that all i can do
the molar weight of hydrogen is 1.008 gram/mol now divide the mass of hydrogen by 1.008 to get the amount of moles
.8928571428571429
right
But we don't have H, we have H2. So the molar weight is not 1.008 but 2.016
0.4464285714285714
right
right. Now do the same for oxygen
oxygen moar weight is 15.9994 right
yes that's the molar mass of an oxygen atom, so what's the molar weight of an oxygen molecule?
7.2 g
Oxygen atom = O Oxygen molecule = O2 just 2*15.9994
31.9988
Yes 31.9988 gram/mol. now we have 7.2 gram oxygen molecules how many moles is that?
0.2250084378164181
right
Yes So we have 0.446 mol H2 and 0.225 mol O2 The ratio of the equation is: 2:1->2 2 mol H2 reacts with 1 mol O2 to produce 2 mol H2O Now we have to find the limiting reactant. This is the reactant that determines how much of the other (excessive) reactant is used in this reaction. The limiting reactant is fully used. Which of the reactants is the limiting reactant?
is it oxygen
Yes. we only have 0.22 mol oxygen and in the ratio only 1 mol oxygen is used and 2 mol hydrogen. which means we need the double amount in mol hydrogen (which is 2x0.22 = 0.44) This is exactly the amount of moles hydrogen we have so both reactants are fully used. Now we calculate how many moles H2O we get from this reaction. we do this by taking the limiting reactant (oxygen) and the ratio of the limiting reactant and the product. This ratio is 1:2 1 mol oxygen is used to produce 2 mol water vapor but we only have 0.22 mol oxygen. how many mol water vapor can we produce with that?
i dont know that
1 mol oxygen = 2 mol water vapor 0.22 mol oxygen = ? mol water vapor
3 i guess
Well that's a very strange guess. The only think you have to do is multiply it by 2
.44 srry
Yes, now the last step is to convert 0.44 mol H2O to grams any ideas?
give me steps
Just the reverse of what we did to convert grams to moles. multiply by molar mass. what is the molar mass of H2O?
2.0158
how is that possible? the mass of 1 oxygen atom is already 16 gram/mol
correct me please
Do determine the molar mass of a compount, just break it into pieces. We can break H2O in 2 pieces. 2x H and 1x O just take the molar mass of H and multiply it with 2 then take the molar mass of O and add it to the H's
ok
so hydrogen is 2.01588 when multiplied by two and the moler mass of oxygen is 31.9988
hydrogen is 1.008 we're talking about atoms here. not molecules so only 1 H
2* H= 2*1.008 = 2.016 1* O= 1*15.9994= 15.9994 ------+
i will understand this if you jusr do it and then explain after the problem
just add 2.016 and 15.9994...
18.01
right
Yes. now multiply that with the amount of moles H2O we have and you'll have the answer
again how much h20 moles
we just calculated that, are you even trying to understand this? scroll back up to see it
yes
2.01588
is that the mole
no... 0.22 gram/mol
of h20
0.22 is the mole
yes but we have 2 mol h2o in the equation right? So that would be 0.44 mol H2O Now just multiply that with the molar mass of water to get the grams
7.9244
right
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