Question

Lim Sin(x)/x^2+3x
x->0

Answer 1

\[\lim_{x\to 0}\frac{\sin(x)}{x}=1\]

Answer 2

so
\[\lim_{x\to 0}\frac{\sin(x)}{x(x+3)}\] is what you have to compute
break it in to two parts

Answer 3

i guess to be more precise i should say "write as a product"

Answer 4

so you get \[\lim_{x \rightarrow 0} \frac{ 1 }{(x+3) } =1 ??\]

Answer 5

so the limit is 1/3?

Answer 6

your answer is correct, but i assume you meant \[\lim_{x \rightarrow 0} \frac{ 1 }{(x+3) } =\frac{1}{3} \]

Answer 7

yea ahah thanks i forgot the /3 thank you!

Answer 8

yw