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@Ray10 same matrix but A^-1 if you wouldnt mind :)
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okay so A= \[\left[\begin{matrix}2 & 1 \\ 3 & 2\end{matrix}\right]\] correct? to work out the inverse you can follow this formula \[\frac{ 1 }{ ad-bc } (\left[\begin{matrix}d & -b \\ -c & a\end{matrix}\right]\]
to make it easier to understand the formula, with a 2x2 matrix, to find it's inverse, you switch the positions of "a" and "d" and times "b" and "c" by -1
can you work out the inverse from that? :)
@sky202 hope that helped!
thanks :)
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