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The limit of (1-cos3x)/x as x approaches 0
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Use L'hopital's rule... lim (1-cos(3x))/x = lim 3sin(3x) = 0 x->0 x->0
If you don't know L'Hopital's rule yet, use the known limit: \[\lim_{x\to0}\frac{1-\cos ax}{ax}=0\] Given function can be expressed as follows: \[\lim_{x\to0}\frac{1-3\cos x}{x}\cdot\frac{3}{3}=3\lim_{x\to0}\frac{1-\cos3x}{3x}\]
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