find the solutions to the systems of nonlinear equations: y=2x x^2+y^2=15
substitute and solve
y = 2x => x^2 +(2x)^2 = 15
I think I am doing that but I dont know if I'm getting the right answer or working the problem right
what did you get?
x = square root of 3 and negative square root of 3 y = 2 square root of 3 and -2 square root 3
there you go... except it should be two points so write them as pairs (x, y)
Oh okay sweet :D thanks for the tip ! could you help me with one more problem similar to this one?
let's see
x^2 + y^2= 25 x^2 -y^2 --- --- = 1 5^2 5^2 I don't know on which equation to start with
solve the first for one of the variables and plug it into the second.
So move the y^2 to the other side then square root everything?
no need to sqrt.
so just flip the y^2 to the other side? x^2 = 25 - y^2
yeah, that'll work
so replace the x^2 with 25 - y^2
you can do that... i'd do y^2 = 25 - x^2
how come is it easier to do it with y first?
it really doesn't matter
oh ok I thought you HAD to start with y first lol
no
going for dinner, i'll be back later
oh ok im working through the problem right now
you should get 4 points
you multiply the denominator by 25 right? or 5
25
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