How do you find the derivative of 9/(5-x)
what r ur suggestions for answers?
I'm a little lost all together, do I have to use the quotient rule in this case?
idk ill figure that out for u.
Thanks
ur welcome
do u mean the distributive?
the quotient rule of f' (x)g(x) - f(x) g'(x) all divided by g(x)2
you do not have to use the quotient rule that i know of
so how would i go about it
ill explain. but read this carefully k? i am using this sigh # for divide k?
ok
so the answer is. (9#5)-(9#X) ur just dividing 9 by all the numbers or letters in the paranthesis. make sense?
so 9/5 - 9/x? why is that?
you can use quotient rule, but there's a simpler way to get the derivative treat that as \(9*(5-x)^{-1} \) seee, now there's no denominator....
idt thats right im in college math.
I can use the power rule after that right? then it would come out to be -9 *(5-x)^0?
I am too
okay and i dont think so
you can use power rule, but have you been yet taught the chain rule ?
No we haven't talked about the chain rule yet
then you must use here the Quotient rule!
you know the formula can you figure out whats f(x) and g(x) in it ?
thats where i get lost
the numerator is f(x) and denominator is g(x) as simple as that
9/(5-x) 9 (5 - x)^-1 - 9(5 - x)^-2 (-1) chain rule 9/(5 - x)^2
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