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Mathematics 13 Online
OpenStudy (anonymous):

How do you find the derivative of 9/(5-x)

OpenStudy (anonymous):

what r ur suggestions for answers?

OpenStudy (anonymous):

I'm a little lost all together, do I have to use the quotient rule in this case?

OpenStudy (anonymous):

idk ill figure that out for u.

OpenStudy (anonymous):

Thanks

OpenStudy (anonymous):

ur welcome

OpenStudy (anonymous):

do u mean the distributive?

OpenStudy (anonymous):

the quotient rule of f' (x)g(x) - f(x) g'(x) all divided by g(x)2

OpenStudy (anonymous):

you do not have to use the quotient rule that i know of

OpenStudy (anonymous):

so how would i go about it

OpenStudy (anonymous):

ill explain. but read this carefully k? i am using this sigh # for divide k?

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so the answer is. (9#5)-(9#X) ur just dividing 9 by all the numbers or letters in the paranthesis. make sense?

OpenStudy (anonymous):

so 9/5 - 9/x? why is that?

hartnn (hartnn):

you can use quotient rule, but there's a simpler way to get the derivative treat that as \(9*(5-x)^{-1} \) seee, now there's no denominator....

OpenStudy (anonymous):

idt thats right im in college math.

OpenStudy (anonymous):

I can use the power rule after that right? then it would come out to be -9 *(5-x)^0?

OpenStudy (anonymous):

I am too

OpenStudy (anonymous):

okay and i dont think so

hartnn (hartnn):

you can use power rule, but have you been yet taught the chain rule ?

OpenStudy (anonymous):

No we haven't talked about the chain rule yet

hartnn (hartnn):

then you must use here the Quotient rule!

hartnn (hartnn):

you know the formula can you figure out whats f(x) and g(x) in it ?

OpenStudy (anonymous):

thats where i get lost

hartnn (hartnn):

the numerator is f(x) and denominator is g(x) as simple as that

OpenStudy (kenljw):

9/(5-x) 9 (5 - x)^-1 - 9(5 - x)^-2 (-1) chain rule 9/(5 - x)^2

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