Question

ater (3110g ) is heated until it just begins to boil. If the water absorbs 5.01×105J of heat in the process, what was the initial temperature of the water?

Answer 1

do you get it

Answer 2

Using dimensional analysis, I came up with 334.516K as the initial temperature. I am going to try and check it, though, with an eq.

Answer 3

I also got the same answer when using the heat capacity eq, C=dQ/dT. Plugging the knowns in, I found that the dT was 119.685 K*kg. I then divided that by the kg of water present to find the change in temp and then subtracted that from 373K.

Answer 4

I feel fairly confident in my answer, but hopefully somebody can provide an answer that uses a more formal eq.

Answer 5

ohh okay so answe is 334.516K

Answer 6

I believe so

Answer 7

IT SAYS TRY USIND A DIFFERENT TEMP SCALE

Answer 8

my sln: q = m*Cs*(T2 - T1) (in our case T2 = 373K boiling T)
5.05*10^5J = 3110*4.18*(373-T1)
from there T1 = 334.2K
334.2K - 273 ~ 61 Celsius

Answer 9

61 IS ANSWER

Answer 10

IT SAYS IT WANT USING DIMENSIONS OF TEMP

Answer 11

I wrote that..334K is 61Celsius degree...
334K - 273 = 61 C

Answer 12

K - 273 = C

Answer 13

334