Find the 10th term of this sequence..
\[\frac{ 1 }{ 16 },\frac{ 1 }{ 4 },1,4\]
\[a_n=a_1+(n-1)d\] a1 is the first term of the sequence d is the common difference n the number of term to find
but without looking at the formula, notice how things are multiple of 4 to the right, and division of 4 if you want to go to the left. to the right, after 4 is 4x4 = 16, then 16x4 =64 and so on…
yes multiple of 4 both, but what would be the 10th sequence?
You can use the formula she posted or keep multiplying 4 until you get to the 10th
so multiply 64 by 4?
Yea, keep multiplying until you get to the 10th term and if i did it correctly, the 10th term would be 24384
thank you
You are welcome! Btw, a little correction, this is a geometric sequence not arithmetic so you can't use that formula, you have to use the geometric formula. :) Hope I helped
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