Question

Need a little bit of guidance on how to resolve this: A rope suspended from a ceiling supports an object of weight W at its opposite end. Another rope tied to the first at the middle is pulled horizontally with a force of 30N. The junction P of the ropes is in equilibrium. Calculate the weight W and the tension in the first rope.

Answer 1

f=mg
g= gravity

Answer 2

@Jesther I know that. The difficulty I have here is the fact that only one variable was given (horizontal axis) and no angle. That makes it three unknowns. Really confusing...

Answer 3

we already tackled that question, i forgot

Answer 4

how do you mean, @Jesther ?

Answer 5

what??

Answer 6

you tackled this question, where?

Answer 7

in our class

Answer 8

And you forgot. That's really helpful.

Answer 9

yeah

Answer 10

is that net force??

Answer 11

tension in the suspended rope and the weight of the object are what we need here.

Answer 12

A rope suspended from a ceiling supports an object of weight W at its opposite end

i think that is the clue word.. "opposite end"

Answer 13

Does the following formula make sense?
\[T=\sqrt{W^2+30^2}\]

Answer 14

Then, weight in the rope would be: \[W_R=\frac{ W }{ \sqrt{1+(30/W)^2}}\]and force in the rope:\[F_R=\frac{ 30 }{ \sqrt{1+(W/30)^2} }\]\[T=F_R+W_R=\frac{ 30^2 }{ \sqrt{30^2+W^2} }+\frac{ W^2 }{ \sqrt{30^2+W^2}}=\sqrt{30^2+W^2}\]

Answer 15

Thank you @CarlosGp, but that doesn't seem like a solution. We still have two unknowns.

Answer 16

pls give the diagram