Algebra help/instruction please?
This looks to be a very simple problem but for the life of me I cant figure it out. Any help would definitely be appreciated :)
The first step in these sort of things is getting rid of the denominators. Could you? :)
Would I multiply them?
The two big fractions? no.
Argh, I meant the denominators, my bad.
(x+1/5) 5 = (2x-2/6) 6 Am I on the right track or not at all lol
5x+1 = 12x-12 ?
Well, you do have to multiple both sides of the equation by the same number...
Ahh, okay. One moment.
(x+1/5) 5 = (2x-2/6) 5 ?
Here, for everybody's benefit: \[\Large \frac{x+1}{5}=\frac{2x-2}{6}\]
Haha thanks
If you're having a hard time doing these things, then my suggestion is take things slowly, one step at a time, and don't worry, you'll get faster. Let's get rid of this denominator:\[\Large \frac{x+1}{\color{red}5}=\frac{2x-2}{6}\]
Thanks @terenzreignz .... Now @TheToneOfSurprise what do YOU think?
5(x+1/5) 5x + 5
No. \[\Large 5\times \frac{x+1}{5}=\cancel5\times \frac{x+1}{\cancel5}\]
Look at $$\huge \frac{2x-2}{6}$$do you see a simplification? @TheToneOfSurprise
Oh duh, that's right - it cancels out. Sleep deprivation is not recommend lol.
Would we do the same thing to that side?
Hang on. Let Skull finish...
1x-1/3 as a simplification, maybe?
$$\huge \frac{2x-2}{6}= \frac{2(x-1)}{2*3} $$
cross multiplication works aswell, but its good she is getting wat u saying @terenzreignz
That's good @TheToneOfSurprise So our equation becomes \[\Large \frac{x+1}{\color{red}5}=\frac{2x-2}{6}\] \[\Large \frac{x+1}{\color{red}5}=\color{blue}{\frac{x-1}{3}}\] Mind you, that simplification isn't strictly necessary, but you might make it a habit to simplify when possible, it does just that...it SIMPLIFIES things.
Ready to continue?
Yep, so far so good.
go ahead @terenzreignz Great job!
\[\Large \frac{x+1}{\color{red}5}=\color{}{\frac{x-1}{3}}\] Now, you already know that to get rid of that 5-denominator, you multiply it by 5, right?
Can we just multiply 5 like this: \[\Large 5\cdot\frac{x+1}{\color{}5}=\color{}{\frac{x-1}{3}}\qquad \color{red}?\]
Yes, we would end up with x +1, I believe.
My question ^
Nope, what we do to one side we have to do to the other, right?
Very good :) Multiplying 5 only to one side 'isn't fair' so to speak. We must be fair XD
\[\Large 5\cdot\frac{x+1}{\color{}5}=\color{}{\frac{x-1}{3}}\qquad \Huge \color{red}\times\]
\[\Large \color{red}5\cdot \frac{x+1}{\color{red}5}=5\cdot\color{}{\frac{x-1}{3}}\qquad\Huge \color{green}\checkmark\]
Can you simplify?
x + 1 = erm...
5x-1/15 or x-1/15 or... im not sure tbh :p
Whoops... Simplify just the left-side, please...
Oh haha. x+1 ?
Good... good... \[\Large \color{blue}{x+1}=5\cdot\color{}{\frac{x-1}{3}}\] Now simplify the right-side.
I still am unsure lol. But 5x-1/15 or x-1/15 would be my two guesses.
Both of them wrong. But that's what we aim to fix. ^_^ Better you make your mistakes now than during exams, yeah? \[\Large \color{green}a\cdot \frac{p}q = \frac{\color{green}ap}q\] did you understand that? :) when you multiply a number by a fraction, you just multiply it to the NUMERATOR. And mind you, the WHOLE numerator. Now, simplify the right-side of\[\Large \color{blue}{x+1}=5\cdot\color{}{\frac{x-1}{3}}\] again.
Ooh, so would it be 5x-1/3? :)
;-; I messed up
5x-5/3
Great. You made a mistake, but you corrected it yourself. Don't worry... soon you'll be wondering if algebra was hard at all ^_^
\[\Large \color{}{x+1}=\color{blue}{\frac{5x-5}{3}}\]
Yay for progress B)
Now, get rid of that 3-denominator. I trust you can do it yourself, now? ^_^
3(5x-5/3) x+1 = 5x - 5 -1 -1 x=5x-6
Wait no I've done it wrong again ;_;
You... have been unjust again -_- :D
The injustice of only multiplying the right-side by 3 and not the left... There is no order in the universe D:
Think of it as a balance.
^ <nods>
3(x+1)=3(5x-5/3) 3x+3 = 5x-5 -3 -3 3x = 5x - 8 -5x -5x -2x = -8 /-2 /-2 x = 4
I think. That I. Have done the thing.
Applause is in order? @skullpatrol ?
Is there any better way to celebrate a job well-done... than by CONFIRMING it? :D \[\Large \frac{x+1}{5}=\frac{2x-2}{6}\]
>.>
\[\Large x = \color{blue}4\]
\[\Large \frac{4+1}{5}=\frac{2(4)-2}{6}\]
\[\Large \frac55 = \frac{8-2}6\]
I suppose I can do the thing :p 4 + 1 / 5 = 2(4)-2/6 5/5 = 8-2/6 5/5 = 6/6
\[\Large 1 = 1 \qquad \Huge \color{green}\checkmark \]
You did extremely well ^_^
Not yet perfect, but you'll get there soon :)
I really appreciate all of your help @terenzreignz and @skullpatrol ^_^
You can call me TJ. And no problem ^_^
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