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Chemistry 6 Online
OpenStudy (anonymous):

1 L of 0.25 M of solution of NaCl

OpenStudy (anonymous):

question?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

what are you asking for?

OpenStudy (anonymous):

Explain how to make 1 L of 0.25 M solution of NaCl

OpenStudy (anonymous):

mole of NaCl / volume of solution of NaCl = Molarity of solution of NaCl mole of NaCl / 1L = 0.25M mole of NaCl = 0.25 mole mass of NaCl = molar mass of NaCl * mole of NaCl mass of NaCl = 58.5 g/mol * 0.25 mole mass of NaCl = 14.6 g what you have to do is to mix 14.6 g of NaCl with approximately 1L of water..

OpenStudy (anonymous):

Thank you so much!!!

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