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Verify the Identity. PLease help :) cos x sin x + 2 cos^2 x - sin x -2 cos x ____________________________________ = cos x -1 sin x + 2 cos x
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in the numerator from first two take common cos x and from last two -1 and make factors.
is sine the common factor? is this factoring by grouping?
cosx (sin x+2 cos x) similarly for second
\[ \cos x \sin x + 2 \cos^2 x - \sin x -2 \cos x = \cos x(\sin x+2\cos x)-\sin x -2\cos x \]
\[ =\cos x(\sin x +2\cos x)-(\sin x +2\cos x) = (\cos x -1)(\sin x +2\cos x) \]
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The numerator and denominator cancel out.
This identity only holds true when: \[ \sin x +2\cos x \neq 0 \]
I understand now, Thank you :)
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