range of f(x)=2/x^2-2x-3 i know the domain is all real numbers except 3 and -1
and the range of f(x)=x^2+x-2/x^2-3x-4 i know the domain is all real numbers except 4 and -1

Question

range of f(x)=2/x^2-2x-3 i know the domain is all real numbers except 3 and -1 
and the range of f(x)=x^2+x-2/x^2-3x-4 i know the domain is all real numbers except 4 and -1

anonymous · Answer

You can obtain the range of the two functions in this way: For the first function, when x tends to negatively/positively infinite we get a o for both. and when x tends to the roots of denominator, we get an infinity

anonymous · Answer

i dont really get that . i graphed it and i was told to look at the y values and identify any any gaps or missing values is that right ? @Saeeddiscover

anonymous · Answer

Graphing it is a great help, but including some analysis of the extremes, as Saeeddiscover suggested is more precise.

anonymous · Answer

Are you familiar with the 'Limit' process? Had any calculus? If so, that'll help too. Otherwise, look at the graph for any maximum or minimum value, and if there is none, then look for gaps.

anonymous · Answer

This is for pre cal and oh okay thanks ! @CliffSedge @Saeeddiscover

anonymous · Answer

For the first one there are no maximum or minimum values so that means it has infinity

anonymous · Answer

Just be careful how to express the range. Two standard forms are inequality notation: -∞ < y < ∞
and interval notation: (-∞ , ∞)

anonymous · Answer

Determining of the range of most functions is somehow impossible, but we sometimes do that only for rational functions where both functions upper and lower the fraction are polynomials. I can show them if you know at least a bit processes of limitation.....

phi · Answer

Here is one way to do the analysis