What is the solution of the following system? -3x - 2y = -12 9x + 6y = -9
Is there a particular method we are supposed to use?
It does not state a method :(
I sense a problem with this system. After multiplying the top equation by 3 and adding the two together, it kinda falls apart.
Solving both equations for y to get slope-intercept form will also point out this particular feature.
My available answer choices are; no solutions, infinitely many solutions, (2,1) or (-2,-1)
Ok, in that case, elimination is probably the simplest and easiest route for this one. You would multiply the top equation by 3 to get \(-9x-6y=-36\) You would add that together with the bottom equation. \(\cancel{-9x}-\cancel{6y}=-36\) \(\cancel{9x}+\cancel{6y}=-9\) \(0\ne-45\) No solution.
In all honesty, this problem was mostly busy work....
Busy work + knowledge of a concept: It's important to know what 'no solution' means in this context, i.e. the two lines are parallel (have identical slope) and therefore do not intersect.
Thank you all so much for your help!!!
True, if you solve them both out for \(y\) you should be able to see this. \(-3x - 2y = -12\\ -2y=3x-12\\ y=\color{blue}{-\dfrac{3}{2}x}+6\) \(9x + 6y = -9\\ 6y=-9x-9\\ y=\color{blue}{-\dfrac{3}{2}x}-9\)
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