Question

(5w+2)^2-121

Answer 1

I suppose you have to factorize this,
Do you? :D

Answer 2

yesssss

Answer 3

Do you know this algebraic Identity
\[a^2 - b^2 = (a+b)(a-b)\]

Answer 4

yess i do

Answer 5

So just use that over here
We know that 121 is 11 squared so
We can also write your question as...

\[(5w+2)^2 - 11^2 = (5w+2+11)(5w+2-11)\] [Where a = 5w+2 and b = 11]

Understood this? :)

Answer 6

would the answer be 25w+20w-117 ?

Answer 7

@AkashdeepDeb

Answer 8

hmmm, are you supposed to give a standard form, or a factored form will do?

Answer 9

You have to factorize it.
That means it should REMAIN as multiples and not a simple expression that can be added and subtracted,
12 can be factorized as 3x4 and not as 13-1
a^2 - b^2 = (a+b)(a-b) as factors.

So calculate IN the brackets but do not open them.

Understood? :)

The answer would be
\[(5w+13)(5w-9)\]

Okay?