Question

finding this angle measurement in trig?

Answer 1

i need to find the angle measurement for W

Answer 2

yes

Answer 3

First you can find v, using 65* and the hyp=15.

You have sin65=opp/hyp

so sin65*=v/15

solve that for v.

Answer 4

Once you have v, then you can use it again:

sin(w)=opp/hyp

so sin(w)=v/21

That gives you the sine value of w, so then you use the inverse sine function to find w.

Answer 5

thank you so much

Answer 6

alright still confused, i need help finding v

Answer 7

hmmm you only need angle W right?

Answer 8

keep in mind that
\(\bf cos(\theta) = \cfrac{\textit{adjacent side}}{\textit{hypotenuse}} \implies cos(w) = \cfrac{\textit{adjacent side}}{\textit{hypotenuse}}\\ \implies cos^{-1}(cos(w)) = cos^{-1}\left(\cfrac{\textit{adjacent side}}{\textit{hypotenuse}}\right)\\ \implies w = cos^{-1}\left(\cfrac{\textit{adjacent side}}{\textit{hypotenuse}}\right)\)

Answer 9

hmmmm,.... you don't have ... the adjacent either ..nevermind that, one sec

Answer 10

\(\begin{array}{lllll}\\
sin(\theta) = \cfrac{\textit{opposite side}}{\textit{hypotenuse}}\\

sin(65^o) = \cfrac{\textit{opposite side}}{\textit{hypotenuse}} \implies sin(65^o) = \cfrac{v}{15}\\ \implies \bf sin(65^o)\times 15 = v\\
\hline\\
sin(w) = \cfrac{\textit{opposite side}}{\textit{hypotenuse}} \implies sin(w) = \cfrac{v}{21}\\ \implies sin^{-1}(sin(w)) = sin^{-1}\left(\cfrac{v}{21}\right) \implies
\bf w = sin^{-1}\left(\cfrac{v}{21}\right)


\end{array}\)