how do you graph y=x^2-4x+7?

Question

anonymous · Answer

First you have to find the line of reflection, since quad eq. symmetric.

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anonymous · Answer

In that equation, y = x^2 the line of reflection is x = 0

anonymous · Answer

The figure I drew, I mean

anonymous · Answer

like how do i know where to put the points because i need to label the vertex and axis of symmetry

anonymous · Answer

The axis of symmetry IS the line of reflection.

Since x = "Whatever you got for the axis of symmetry", then you can subsitute x for that in the quadratic equation, giving you the value for the y, giving you (x,y), giving you the vertex!

jdoe0001 · Answer

hmm, you know the components  a  b  and c for that, right?

jdoe0001 · Answer

that is for $\bf ax^2+bx+c$

anonymous · Answer

a=x^2 b=4x and c=7

jdoe0001 · Answer

well, just the coefficients only

anonymous · Answer

i have no idea.... im sorry! im terrible at math.

anonymous · Answer

what exactly would the coefficiets be?

anonymous · Answer

a = 1
b = 4
c = 7

jdoe0001 · Answer

$\large \begin{array}{lllll}\
 y=&1x^2&-4x&+7\
&a&b&c

\end{array}$

jdoe0001 · Answer

just the coefficients though
thus a = 1, b = -4 and c = +7

anonymous · Answer

ok and then i plug that into the quadratic equation?

anonymous · Answer

Quadatic equations only find the value of x when y = 0. It won't really do any help when graphing multiple points.

anonymous · Answer

ok

jdoe0001 · Answer

so to get the vertex for a parabola like so
notice that that the leading coefficient, that is, the "a" component is positive, that means is going upwards

anyhow to get the vertex of it, the coordinates of it will be at $\bf \left(-\cfrac{b}{2a}\quad , \quad c-\cfrac{b^2}{4a}\right)$

anonymous · Answer

No, I think it would be

(-b/2a, f(-b/2a))

jdoe0001 · Answer

same thing

anonymous · Answer

and that finds the vertex every time?

jdoe0001 · Answer

yes

anonymous · Answer

Yes, for equations like "ax^2 +bx+c=f(x) or y

anonymous · Answer

thank you so much! you don't understand how much you've helped! i learn more here than in my actual class. thanks again! :)

jdoe0001 · Answer

yw

anonymous · Answer

That is the power of Open Study.

anonymous · Answer

i'll defiantly be coming on here more often haha

anonymous · Answer

We hope to answer more of your questions!

anonymous · Answer

pretty sure i'll have more after i finish this one hahaha