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Mathematics 17 Online
OpenStudy (anonymous):

what is the domain of this function? and how

OpenStudy (anonymous):

\[y=\log_{3} x+2\]

OpenStudy (anonymous):

is it x + 3 or logbase3(x + 2)

OpenStudy (anonymous):

sorry, 2:P

OpenStudy (anonymous):

\[y=\log_{3} (x+2)\]

OpenStudy (anonymous):

ok. so in that case the domain is all x > -2

OpenStudy (anonymous):

how did you get this?

OpenStudy (anonymous):

This is because the argument of a log has to be positive.

OpenStudy (anonymous):

oooh wait you just got the inverse of (x+2)?

OpenStudy (anonymous):

Not quite an inverse, but sinusoidal's reasoning is correct. Given log(A), A > 0. log(x+2) --> x+2 > 0 Logarithms are exponents and there is no exponent that can make a base zero or negative.

OpenStudy (anonymous):

mmm i see thank you very much guys!

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