Question

For the following system, use the second equation to make a substitution for x in the first equation.

x + 5y - 10 = 0
x = 2y - 8

What is the resulting equation in simplest form?


-3y - 18 = 0
3y - 18 = 0
7y - 18 = 0

i got a

Answer 1

Mr. Dan give me a moment I work better with paper and pencil on these types of questions :-).

Answer 2

thanks and ok

Answer 3

I take this is Algebra II?
Anyway here is my work:
x + 5y - 10 = 0
x = 2y - 8

2y - 8 + 5y - 10 = 0

7y - 18 = 0

y = 2.57142857143

(I'll prettify this with LaTeX in a second.)

Answer 4

C

Answer 5

I take this is Algebra II?
Anyway here is my work:
First equation: \[x+5y−10=0\]
Second equation: \[x=2y−8\]
They want us to use the above equation to get a solution for: \(x+5y−10=0 \)
Input \(2y−8\) for \(x\)
So:
\[2y−8+5y−10=0\]
\[2y+5y=7y\]
\[−8−10=−18\]
So the equation in the simplest form is:
\[7y−18=0\]