Question

An object projected up with initial velocity v attains a height h. Another object projected up with initial velocity 2v will attain what height? I know the answer is 4h but I can't see why.

Answer 1

Here is how:
h is directly proportional to square of v.
so le v0 be v1 and 2v0 be v2 and h1 is h.Here we should find h2.

so from the relation h1/h2 = v1^2/v2^2
h/h2 = v0^2/(2v0)^2
h/h2 = 1/4
Therefore h2 = 4h

Answer 2

Due to the earth's gravity constant (9.8 m/s/s), the object will fall in the shape of a parabola.



If initial velocity was 1:
\[1^{2} = 1\]

If initial velocity was 2:
\[2^{2} = 4\]

Hope this helps.