Computing the integral of a vector over closed path? can someone help me with this problem let v=(-y/x^2+y^2 , x/x^2+y^2) compute the integral of v over a cirlcle C(0,R) compute integral of v over a closed path gamma
You need the parametrization of the circle so that you can get \(\mathbb{v}(\mathbb{r}(t))\cdot \mathbb{r}'(t)\).
and what about the path gamma ?
can you post the solution please
What's the radius of the circle?
(0,r) that's what the problem says
Hmm... let's assume that the radius of the circle is some number \(a\) and the center of the circle is (0,R). The circle can be parametrized by letting \(\mathbf{r}(t)=(a\cos(t)+0)~\mathbf{i}+(a\sin(t)+R)~\mathbf{j}, \; 0\leq t\leq2\pi\) so that \(\mathbf{r}'(t)=-a\sin(t)~\mathbf{i}+a\cos(t)~\mathbf{j}\). Now, since \[\mathbf{v}(x,y)=\frac{-y\mathbf{i}+x\mathbf{j}}{x^2+y^2}\] can you find \(\mathbf{v}(\mathbf{r}(t))\)?
I really don't know how to, do you mind if you showed me please kind stranger :)
Just substitute the values of x(t) and y(t) from r into v.
ok thanks , and for the path gamma what should i do ?
Oopsies. I called it r instead of \(\gamma\). Just pretend the r's are gamma.
alright thanks
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