Let f(x) = 2x - 6 Solve f-1(x) when x = 2.
\[\large f(x) = 2x - 6\] \[\large y = 2x - 6\] \[\large x = 2y - 6\] \[\large x+6 = 2y\] \[\large \frac{x+6}{2} = y\] \[\large y = \frac{x+6}{2}\] \[\large f^{-1}(x) = \frac{x+6}{2}\] \[\large f^{-1}(2) = \frac{2+6}{2}\] \[\large f^{-1}(2) = ???\]
So, the answer would be -2 ?
no
4?
you need to evaluate \(\large \frac{2+6}{2}\)
8 over 2 which equals 4?
2 + 6 = 2 if you divide that by 2 that would be 6 ? but, thats not an answer choice @jim_thompson5910 sorry, im a bit confused ..
\(\large \frac{2+6}{2} = \frac{8}{2} = 4\)
not sure how you're getting 2+6 = 2
thats what i said! 4..
yes I know henry
I suck at math, but thankyou !!
I'm writing it for Nurialozza96
lol i should get a Best Response huh
I'm sure she's just fine at it, she just needs more practice, that's all
@henryarias5 you're childish, get off my page please. goodbye. and @jim_thompson5910 thankyouuuu !!!
you're welcome
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