if vector A=5i, B sub z=0, absolute value of vector B=7, vector A x vector B=2.5k, find vector B
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OpenStudy (anonymous):
\[
\mathbf A=5\mathbf{i}+0\mathbf{j}+0\mathbf k
\]
OpenStudy (anonymous):
\[
\mathbf B=b_x\mathbf{i}+b_y\mathbf{j}+0\mathbf k
\]
OpenStudy (anonymous):
First do the cross product.
OpenStudy (anonymous):
but what pouts do i use for bi and bj
OpenStudy (anonymous):
Keep them as variables \(B_x\) and \(B_y\)
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OpenStudy (anonymous):
i got o,o,5By
OpenStudy (anonymous):
Notice how: \[
5B_y=2.5
\]
OpenStudy (anonymous):
Now you can find \(B_y\)
OpenStudy (anonymous):
you lost me, the 2.5 comes from b=k right?
OpenStudy (anonymous):
vector A x vector B=2.5k
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OpenStudy (anonymous):
\[
\mathbf A\times \mathbf B =2.5\mathbf k
\]
OpenStudy (anonymous):
\[
2.5\mathbf k = 5B_y\mathbf k
\]
OpenStudy (anonymous):
ok that was given...
OpenStudy (anonymous):
so By=.5?
OpenStudy (anonymous):
Yes.
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OpenStudy (anonymous):
Now: \[
\sqrt{B_x^2+B_y^2+0^2}=7
\]
OpenStudy (anonymous):
Because \[
\|\mathbf B\|=7
\]
OpenStudy (anonymous):
So \[
B_x^2+B_y^2=7^2
\]
OpenStudy (anonymous):
this is to find Bx?
OpenStudy (anonymous):
Yes.
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OpenStudy (anonymous):
which I'm getting = 48.25
OpenStudy (anonymous):
Bx sqaured+.5^2=49
Bx=48.75?
OpenStudy (anonymous):
You need to do the square root.
OpenStudy (anonymous):
so im getting final answer of 6.98212i+.5j
correct?
OpenStudy (anonymous):
thank you, i learned a different approach
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OpenStudy (anonymous):
\[
|B_x|=\frac{\sqrt{195}}{2}
\]
OpenStudy (anonymous):
There are two answers...
OpenStudy (anonymous):
\[
B_x=\pm \frac{\sqrt{195}}{2}
\]
OpenStudy (anonymous):
i see, from the square root
OpenStudy (anonymous):
A different approach? There is only one approach I can think of. anyway we have the answer. there are two.
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OpenStudy (anonymous):
I'm fairly new at this material
OpenStudy (anonymous):
Do you understand the work we did? Do you understand why there are two answers?
OpenStudy (anonymous):
yes, 2 answers because anytime you square root, you have plus answer and minus answer, and the work we did was, the way i see it, filling in the gaps from the info we got to complete to formula to find the answer