Let f(x) = x - 2 and g(x) = x2 - 7x - 9. Find f(g(-1))
First find g(-1) \[\large g(x) = x^2 - 7x - 9\] \[\large g(-1) = (-1)^2 - 7(-1) - 9\] \[\large g(-1) = 1 - 7(-1) - 9\] \[\large g(-1) = 1 + 7 - 9\] \[\large g(-1) = 8 - 9\] \[\large g(-1) = -1\]
then you use this value of g(-1) to find f(g(-1)) f(x) = x - 2 f(g(-1)) = g(-1) - 2 ... replace each x with g(-1) f(g(-1)) = -1 - 2 ... replace g(-1) on the right side with -1 (since g(-1) = -1) f(g(-1)) = -3
coincidentally, g(-1) = -1, but the input and output are usually not the same
so f(g(-1)) = -3? im starting to understand this lesson
yes correct
i understood everything till f(x) came in the equation lol but thank you! im starting to understand it more
well you start with f(x) = x-2 then you replace x with g(-1) since you want f(g(-1))
so that explains how we got f(g(-1)) = g(-1) - 2 then on the right side you replace g(-1) with -1 because above we've shown that g(-1) = -1
OHHHHHHHHHHHH I see
glad it's clicking now
is easy. its just that if you think it too much it gets confusing
thank you!
yeah just take it one step at a time and you'll be fine
i know! thank you! but what about ? Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)) @jim_thompson5910
what is g(2)?
g(2) = x2 -6x - 7 g(2) = 2^2 - 6x - 7 ???
@jim_thompson5910
you need to replace the x in -6x as well
g(x) = x^2 - 6x - 7 g(2) = (2)^2 - 6(2) - 7 g(2) = ???
yes yes i know that i forgot to type it in tho lol. g(2) = -15?
good
now that you know that g(2) = -15, you basically plug -15 into f(x) and evaluate
im learning better than in class lol. ok let me work that out
this is because f(g(2)) = f(-15) effectively since g(2) = -15
that's great you are
so.... f(x) = x + 8 f(-15) = -15 + 8 f(-15) = -7?
correct
so that means f(g(2)) = -7
wait so the final answer is f(g(2)) = -7? THANK YOU
yep, it is
thank you!
yw
Join our real-time social learning platform and learn together with your friends!