a point moves so that the difference between its distance from (0, 5) and (0, -5) is 8. find the equation of the locus.

Question

anonymous · Answer

Sounds like a hyperbola.

anonymous · Answer

yeah hyperbola again..

anonymous · Answer

They points they gave you are the foci.

anonymous · Answer

wio, how did your SS jump to 90? weezz

anonymous · Answer

Well, I was at 89 before.

anonymous · Answer

I know, but still!
Once upon a time you were at 70 or something around that

anonymous · Answer

You lucky fella! [:

anonymous · Answer

Nonsense, this past week I've been in the upper 80's!

anonymous · Answer

Thanks.

anonymous · Answer

yw! o.o

anonymous · Answer

$$
\sqrt{(5-b)^2}=\sqrt{(-5-b)^2}
$$

anonymous · Answer

Doing this can at least find one of the vertices! @silverxx

anonymous · Answer

We know there is a vertex on $(0,b)$.

anonymous · Answer

can we use also distance formula right?

anonymous · Answer

That is what I just did up there.

anonymous · Answer

$\color{blue}{\text{Originally Posted by}}$ @wio
$$
\sqrt{(5-b)^2}=\sqrt{(-5-b)^2}
$$
$\color{blue}{\text{End of Quote}}$

anonymous · Answer

ah okay okay

anonymous · Answer

$$
(25-10b+b^2)=(25+10b+b^2)+8
$$

anonymous · Answer

I should have wrote:$$
\sqrt{(5-b)^2}-\sqrt{(-5-b)^2}=8
$$

anonymous · Answer

b is 2/5?

anonymous · Answer

Yes!

anonymous · Answer

and how about a?

anonymous · Answer

the answer is 9y^2 - 16x^2 = 144

anonymous · Answer

stated on the book

anonymous · Answer

Don't cheat!!!

anonymous · Answer

@ⒶArchie☁✪ Do you know how to go from here?

anonymous · Answer

no no. i mean this question was one of the questions came up during our quiz and i need to know the steps on how to achieve the right answer..

anonymous · Answer

professor gets the questions on the book..

anonymous · Answer

Oh!

anonymous · Answer

Okay, the next step is to find latus rectum.

anonymous · Answer

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