Solve the following system. Show all your work. 3x-2y+2z=30 -x+3y-4z=-33 2x-4y+3z=42 Please help me I really need your help can you tell me how to do it too I dont get it... I need it ASAP
x
Thank you soo much
You can use elimination to eliminate one variable. Then you will have a system of 2 equations with 2 unknowns to solve.
Look at equations 1 and 2. Can you eliminate x?
yes 2x
Okay let me do that real quick
No. 2x is not eliminating x. Equation 1 has 3x. Equation 2 has -x. Ok so far?
2x+y-2z-3
Is what you get when you eliminate am I correct?
If you multiply equation 2 by 3, you will have -3x. Then when you add the new equation 2 to equation 1, x will be eliminated.
Oh multiply K
Each time you add equations, you need to eliminate a variable.
I really dont understand this..
And I pay attention in class 2...
It is just soo confusing
We'll do it step by step. Here are the two equations 1 and 2 in their original form. Eq.1 3x-2y+2z=30 Eq. 2 -x+3y-4z=-33
Now we keep equation 1 as is and we multioply the entire equation 2 by 3, and write it below eq. 1.
Oh by 3 Okay
Eq.1 3x - 2y + 2z = 30 New Eq. 2 -3x + 9y - 12z= -99
Now we add them together. Notice, the x terms cancel out.
Yes so the equation afterwards will be 7y -10z=-69
Eq.1 3x - 2y + 2z = 30 New Eq. 2 -3x + 9y - 12z= -99 -------------------------------- add 7y - 10z = -69
Correct.
Now we need to pick a different pair of equations and again eliminate x.
Let's use equations 2 and 3.
Okay
Eq. 2 -x+3y-4z=-33 Eq. 3 2x-4y+3z=42 By multiplying Eq. 2 by 2, the x's will be eliminated after adding the two eqs togeher.
so it will be -y-z=9
You must multiply the entire eq 2 by 2. New Eq. 2 -2x + 6y - 8z = -66 Eq. 3 2x - 4y + 3z = 42 ------------------------------ add 2y - 5z = -24
Oh okay
And than after that you get both of the answers that you simplified and and them together
So 7y-10z=-69 2y-5z =-24
Now take the two equations with x eliminated, and you have a system of 2 equations in 2 unknowns.
Correct. Since we are already using elimination, let's continue with that method. 7y - 10z = -69 2y - 5z = -24 Look at -10z and -5z. If we multiply the seciond eq by -2, the z term will become 10z which when added to -10z of the eq above will eliminate z.
This is the part I dont get...
We are using elimination to solve a system of 2 equations n 2 unknowns. Keep eq. as is 7y - 10z = -69 Multiplied by -2 -4y + 10z = 48 ------------------- add 3y = -21 y = -7
So you multiplied the bottom equation by -2 correct?
yes
And what do I do after that I found y but after that do I substitute it in with the other equations?
Now that we have y, we use one of the two equation that have only y and z to find z. Let's use the first one: 7y - 10z = -69, using y = -7: 7(-7) - 10z = -69 Solve for z
-49-10z=-69
Than you add -49 into -69 but the -49 becomes a positive
7(-7) - 10z = -69 -49 - 10z = -69 -10z = -20 z = 2
Thanks!
Correct.
And you get x by doing what...
Now that we have y and z, we go back to one of the original 3 equations that has x, y, and z. We plug in the known values of y and z, and we solve for x.
Let's use the first original equation: 3x - 2y + 2z = 30
3x - 2(-7) + 2(2) = 30 Now you have one equation with only one variable, so you can solve for x.
3x+18=30 x=4
x=4
3x + 14 + 4 = 30 3x + 18 = 30 3x = 12 x = 4
Because 3x=12 divide by 3
Correct.
:D So y=7, z=, 2, and x=4
Thank you soooo much!!!
The solution is: x = 4; y = -7; z = 2
You are very welcome.
Join our real-time social learning platform and learn together with your friends!