Question

Verify the identity (1+ sinx)/(cos x) + (cos x)/(1+sin x) = 2 sec x?

Answer 1

@goformit100 can you help?

Answer 2

Are you Indian ?

Answer 3

no why?

Answer 4

plz help

Answer 5

o.O

Answer 6

I know the answer

Answer 7

Right, hold on @pvs285

Answer 8

(1+ sinx)/(cos x) = (1/cos x + sinx/cos x) = ?

Answer 9

(1/cosx + tanx) right

Answer 10

yes

Now do same for

(cos x)/(1+sin x)

Answer 11

What did you got ?

Answer 12

idk

Answer 13

what is it?

Answer 14

is it cosx+tanx/1?

Answer 15

@goformit100 are you still here?

Answer 16

yes now add them up

Answer 17

(1/cosx+tanx)+(cosx+tanx/1)

Answer 18

My first step would have been to combine the fractions.

Answer 19

(cosx+tanx)(cosx+tanx)/cosx+tanx

Answer 20

what now

Answer 21

plz help

Answer 22

Yeah I don't like all those tangents. I still would have approached it by combining the fractions as a first step.

Answer 23

how do i do that

Answer 24

Force a common denominator by doing:
a/b+c/d =(ad+bc)/(bd)

Answer 25

\[\frac{a}{b}+\frac{c}{d}=\frac{ad+cb}{bd}\]

Answer 26

whats a b c and d

Answer 27

a is the numerator of the first fraction
b is the denominator of the first fraction
c is the numerator of the second fraction
d is the denominator of the second fraction

Answer 28

(cosx*cosx)+(1+sin*1+sin)/(1+sin*cosx)

Answer 29

Or you could write it as
\[=\frac{1+s}{c}+\frac{c}{1+s} \\ =(\frac{1+s}{c}\times \frac{1+s}{1+s})+(\frac{c}{1+s} \times \frac{c}{c})\]
\[=\frac{1+2s+s^2+c^2}{c+cs}\]

Answer 30

I think you wrote:
\[\frac{\cos(x) \cos(x)+(1+\sin(x))(1+\sin(x))}{(1+\sin(x))(\cos(x))}\]
correct?

Answer 31

yup

Answer 32

what now

Answer 33

Now multiply (1+sin(x))(1+sin(x)) out

Answer 34

1+2sinx

Answer 35

+what else

Answer 36

what do i do now

Answer 37

You haven't multiplied (1+sin(x))(1+sin(x)) correctly yet

Answer 38

cos^2x+1+2sinx

Answer 39

is that correct for the numerator