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Mathematics 12 Online
OpenStudy (anonymous):

How do I draw samples of size 3 with replacement from the population 3, 6, 9, 12. I know that it there are going to be 4^3=64 samples but I want to know how do i make these samples?

OpenStudy (anonymous):

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OpenStudy (anonymous):

The fundamental counting principle here is: Suppose one task can be done in \(m\) ways Suppose another task can be done in \(n\) ways Then the number of ways to do these two tasks sequentially is \(m\times n\)

OpenStudy (ybarrap):

R has a "sample" function that is useful for this purpose: http://www.r-project.org/ http://stat.ethz.ch/R-manual/R-devel/library/base/html/sample.html

OpenStudy (anonymous):

Doing the same task \(m\) sequentially \(3\) times is give be:\[ m^3 \]

OpenStudy (anonymous):

correction 1 2 3 in place of 1 2 1

OpenStudy (amistre64):

it might be good to rename the elements as 0,1,2,3 0000 0001 0002 0003 0010 0011 0012 0013 0020 0021 etc ... that would be the easiest what to account for them.

OpenStudy (amistre64):

samples of size 3, even i got confused with all the numbers in the problem ...

OpenStudy (amistre64):

but the concept should still be valid, all i did was draw a set of 4 instead of 3

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