Find a function that models the surface area S of a cube in terms of its volume V. I know the surface area = 6x^2 volume = x^3 S(V)= ???
Volume: V = x^3 solve for x to get x = ??
\(\large \begin{array}{llll} &1ft & = & 12in\\ &1ft^2 & = & 12^2in^2\\ &1ft^3 & = & 12^3in^3\\ \textit{thus we can say}\\ &area & = & x\cdot x\\ &volume& = & x\cdot x \cdot x\\ \hline\\ S(v) = \cfrac{\sqrt{6}\cdot \sqrt{6} \cdot \sqrt{6}x^3}{\sqrt{6} x} \implies 6x^2 \end{array}\)
Hmm, still says it's wrong. I just don't understand q.q
what did you type in exactly?
6x^2
that's the surface area, but it's in terms of the side length and NOT the volume
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