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If f(x) is a polynomial of degree 6 and f(x)=f(2-x) & f(x)=0 has 5 distinct real roots then find sum of all roots of f(x)=0.
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I am guessing we have a repeated root here..
Yep
umm so what next
I'm thinking you could write the general form of \(f\) as follows: \[f(x)=a(x-n_1)(x-n_2)(x-n_3)(x-n_4)(x-n_5)^2\] And \(f(2-x)\) would be \[f(2-x)=a(2-x-n_1)(2-x-n_2)(2-x-n_3)(2-x-n_4)(2-x-n_5)^2\] Then I would think expanding the two and seeing if there's a solution to the system that you get...
can we do this by graph?
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|dw:1379101675466:dw| this is what the solution says..
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