Find an equation of the line that satisfies the given conditions.Through (−6, 5);parallel to the line x = 9

Question

owlcoffee · Answer

for the first use:
$$x-x _{1}=m(x-x _{1})$$
We know that parallel lines have same slope, so you have the initial x, solve for Y.

anonymous · Answer

How?

jdoe0001 · Answer

http://openstudy.com/updates/52337a73e4b0b9d6b2d577a6

anonymous · Answer

That is too confusing

owlcoffee · Answer

Are you 100% that's the text of the problem?

anonymous · Answer

positive

ybarrap · Answer

x=9 is a vertical line. 
Any other vertical line will be parallel to this line. 
If you want the vertical line to go through point, (-6,5), then x=-6 would be a vertical line that also passes through the point (-6,5)

anonymous · Answer

so how would you get the equation?

ybarrap · Answer

The equation is simple: x=-6. This is an equation that includes all values of y, positive, negative and zero. It must. It is required to be parallel to x=9.

ybarrap · Answer

Maybe this makes the situation more clear:
|dw:1379110985859:dw|

ybarrap · Answer

Does this make sense?

anonymous · Answer

Can you help me with another?

anonymous · Answer

Find an equation of the line that satisfies the given conditions.
Through 
(−1, −2);
  perpendicular to the line 
2x + 5y + 5 = 0

owlcoffee · Answer

Solved that one... http://openstudy.com/users/hannahmarie620#/updates/52338f82e4b0af32a078d43c