Check my answer please. (incoming)

Question

anonymous · Answer

$$\frac{ 2x }{ x+5 }+\frac{ 7 }{ x }-4=\frac{ 50 }{ x^2+5x }$$

anonymous · Answer

I get x = -5/2 and -3

mertsj · Answer

Multiply each term by the common denominator which is x(x+5)

anonymous · Answer

I did and when I finish out the solution I get $$2x^2+7x+35-4x(x+5)=50$$

Then working through that get

$$-2x-13x-15=0$$

using the big X I get 

$$(-2x-5)(x+3)$$

mertsj · Answer

$$2x^2+7(x+5)-4(x^2+5x)=50$$

mertsj · Answer

$$2x^2+7x+35-4x^2-20x=50$$

mertsj · Answer

$$-2x^2-13x-15=0$$

anonymous · Answer

Which is what I received above so am I getting something wrong with X

mertsj · Answer

$$2x^2+13x+15=0$$
$$(2x+3)(x+5)=0$$

mertsj · Answer

$$x=- \frac{3}{2}, -5$$

anonymous · Answer

how did 

-2x^2-13x-15=0 

become all positive?

mertsj · Answer

Multiply both sides by -1 and see what you get.

anonymous · Answer

mmm, ok I am still receiving the wrong answer for x though

mertsj · Answer

You have to discard the answer x = -5 because the denominator cannot be 0

anonymous · Answer

mmm ok so for restrictions there would be none then

mertsj · Answer

Any number that causes the denominator to be 0 is excluded. So x cannot be 0 and x cannot be -5.  Those are the restrictions.