The average velocity of a car over a certain time interval is 37 mi/h. If the velocity of the car was 65 mi/h at the end of this interval, what was its initial velocity. Assume that acceleration was constant.

Question

anonymous · Answer

you are not given the time interval?

anonymous · Answer

i guess we could call it $t$ and the average velocity is the slope (since acceleration is constant) then solve 
$$\frac{65-x}{t}=37$$ for $x$

loser66 · Answer

is it not that average velocity  $v=\dfrac{v_{final}+v_0}{2}$ we have $v_{final}$= 65, and $v= 37$  we can count the $v_0$ , right?

anonymous · Answer

I'm working on it and found 8 mi/h ?? am i correct:d

loser66 · Answer

I don't know why, I got 9mi/h. My work is 37 = $\dfrac{65 +v_0}{2}$$\rightarrow$ 74 = 65 +$v_0$$\rightarrow$ $v_0$ = 74-65 =9

anonymous · Answer

yep you're right.d

anonymous · Answer

thanks....

loser66 · Answer

ok