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Mathematics 8 Online
OpenStudy (anonymous):

Which of the following inequalities matches the graph? -6x + y < 3 6x + y < 3 6x - y < -3 The correct inequality is not listed

OpenStudy (anonymous):

OpenStudy (anonymous):

help !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (owlcoffee):

First do an analysis for the ecuation and then determine in the graph the right answer.

OpenStudy (anonymous):

thats not really helping me @Owlcoffee

OpenStudy (anonymous):

cant do that if im lost on the problem

OpenStudy (owlcoffee):

okay, okay, let's do this slow: First) look for roots on the line, meaning that you have to look where the line intersects the x-axis second) look for the Y-intersections.

OpenStudy (anonymous):

does it intersect a x-1? @Owlcoffee

OpenStudy (anonymous):

and the y intersect would be 2?

OpenStudy (owlcoffee):

Do this, take the three ecuations and evaluate them: 1) \[-6x+y<3\] 2) \[6x+y=3\] 3)\[6x-y=-3\] All I did was making them equal to cero, so we can create a linear ecuation to start looking more detailed in them.

OpenStudy (anonymous):

cero?

OpenStudy (anonymous):

ok u basically just rewrote the answers right?

OpenStudy (owlcoffee):

Well yeah, pass the x term to the other side.

OpenStudy (anonymous):

what do u mean?

OpenStudy (anonymous):

did u mean to type in zero?

OpenStudy (owlcoffee):

Like this: for example, the first one: y=6x+3

OpenStudy (anonymous):

lol thank god someone that gives examples!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

OpenStudy (anonymous):

ohhhh ok do i always do that when im trying to solve for y?

OpenStudy (owlcoffee):

Yes, are you familairized with the ecuation of the line?

OpenStudy (anonymous):

somewhat im justy really rusty

OpenStudy (owlcoffee):

I'll oil you up a little: the ecuation, the ordinary one is: \[y=mx+b\] Where the x term is the slope and the constant, the y-intersection.

OpenStudy (anonymous):

ok yeah i remember that

OpenStudy (owlcoffee):

good, now. Look at the third ecuation, we end up having a negative x term, and in the graph it's positive. So we can say that the third ecuation is not the answer.

OpenStudy (anonymous):

yeah cause the graph is increasing , right?

OpenStudy (owlcoffee):

Good! now analyze the 1st and the 2nd

OpenStudy (anonymous):

the first and second question?

OpenStudy (owlcoffee):

Ecuations hehe.

OpenStudy (anonymous):

Ecuations ?

OpenStudy (owlcoffee):

-6x + y < 3 6x + y < 3 6x - y < -3 wich we changed to -6x + y = 3 6x + y = 3 6x - y = -3

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

do u always replace it with an = sign to make it easier?

OpenStudy (owlcoffee):

yes, in these kind of problem, you use knowledge you already had to answer it.

OpenStudy (anonymous):

yeah ok so wats next

OpenStudy (anonymous):

@Owlcoffee

OpenStudy (owlcoffee):

Let's analyze the first ecuation when we solve for y. y=6x+3

OpenStudy (anonymous):

-6x + y = 3 why did u change it to this first?

OpenStudy (anonymous):

@Owlcoffee

OpenStudy (owlcoffee):

We are looking on each ecuation indepently so we can deduce if they belong to the graph or not.

OpenStudy (anonymous):

ok ok

OpenStudy (anonymous):

y=6x+3 -3 -3 @Owlcoffee

OpenStudy (anonymous):

y=3x @Owlcoffee ?

OpenStudy (owlcoffee):

If you wanted to simplify it, it would look like this: y=3x+1 And yes, the first ecuation is the correct answer.

OpenStudy (anonymous):

why plus the 1? for rise over run? @Owlcoffee

OpenStudy (anonymous):

@Owlcoffee u said the first one isnt the answer since its a negative??????????

OpenStudy (owlcoffee):

The third one was not correct, since it has a negative x term. y=6x+6, I divided the whole ecuation by 3 to reduce the numbers. I analyzed what happened when y=0 and solved for x. then analyzed for when x=0 and solved for y. and when I graphed that i got a graph equal to the one you put.

OpenStudy (anonymous):

alright u lost me by just giving me the answer so whats the answer for this problem then you probably could help with my next post cuz all these comments u lost me

OpenStudy (anonymous):

@Owlcoffee

OpenStudy (owlcoffee):

Sure, i'll help you :)

OpenStudy (anonymous):

so the answer for this problem was a? @Owlcoffee

OpenStudy (owlcoffee):

yes, it was

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