Question

Checking my answer.

Answer 1

what question

Answer 2

\[\frac{ 4x }{ x-5 }+\frac{ 1 }{ x+5 }=\frac{ -10 }{ x^2-25 }\]

Answer 3

Start off by noting that x cannot be 5 or -5

Answer 4

So getting ride of the bottom I get

\[4x(x+5)+1(x-5)=-10\]

Answer 5

yes

Answer 6

working out to

\[4x^2+20x+x-5=10\]

Com binding my terms I get

\[4x^2+21x-5=-10\]

Answer 7

yes

Answer 8

Now my problem comes with factoring the beginning, putting the number in the big X I get -20 and 21, but there are no numbers that go in there.

Answer 9

Did you add 10 to both sides?

Answer 10

\[4x^2+21x+5=0\]

Answer 11

Ah ok I was for some reason thinking I had to square the right and left but only on problem like

\[(x-3)^2=3\]

So now the number that go in are 20 and 1

Answer 12

so \[\frac{- 1 }{ 4 }\] would be my only answer for X since -5 can not be an answer?

Answer 13

yes

Answer 14

Thanks simple mix up on which method to use. =p

Answer 15

yw