Question

Find the function using f(x)= x+1/x g(x)= x+1/x+2
f o f

Answer 1

\[ f(x)=\frac{ x+1}{x}\]?

Answer 2

its actually x^4+3x^2+1/x(x^2+1) i'm juts not sure how they got that

Answer 3

Yes, you function is
\[f(x)=x+\frac{1}{x}\]
\[f o f=f(f(x))\\=f(x+\frac{1}{x})\\=(x+\frac{1}{x})+\frac{1}{(x+\frac{1}{x})}\]

Answer 4

\[=x+\frac{1}{x}+\frac{x}{x^2+1}\]
\[=\frac{x^2+1}{x}+\frac{x}{x^2+1}\]
Common denominators and you should get what you wanted

Answer 5

ok thank you

Answer 6

Do you understand? You can ask if you don't :)