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Physics 84 Online
OpenStudy (anonymous):

I worked out the problem several times and keep getting the wrong answer I got .00001289604743 for my first try and apparently it's wrong :/ Birds resting on high-voltage power lines are a common sight. A certain copper power line carries a current of 50.6 A, and its resistance per unit length is 8.26 × 10−5 Ω/m. If a bird is standing on this line with its feet 7.9 cm apart, what is the potential difference across the bird’s feet? Answer in units of V

OpenStudy (anonymous):

@Arctangent

OpenStudy (anonymous):

I did R=(8.26 x 10^-5) 7.9/50.6

OpenStudy (anonymous):

@ankit042

OpenStudy (ankit042):

Resistance is given per unit length. Now you have to find resistance for 7.9 cm so R = (8.26 x 10^-5)*7.9/100 then use V=IR

OpenStudy (anonymous):

So .00033018524

OpenStudy (anonymous):

Can I ask my second question now?

OpenStudy (anonymous):

A potential difference of 12 V is found to produce a current of 0.3 A in a wire of length 3.4 m with a uniform radius of 0.34 cm. What is the resistance of the wire? Answer in units of Ω What is the resistivity of the wire? Answer in units of Ω · cm

OpenStudy (anonymous):

I got 40 for the first one and it is right I tried applying the answer to the second part of the question and its coming out wrong I did 40=resistivity sign(3.4/.3631681108)

OpenStudy (ankit042):

Yes 40 is correct! now this is same as we did the last question. R= (resistivity)*length/Area now you have to calculate the area of circle. Make sure you convert all the distance units to cm. Because we have to answer in ohm cm

OpenStudy (anonymous):

so resistivity x .034 then divide by .3631681108

OpenStudy (ankit042):

I think so!

OpenStudy (anonymous):

but how would I write that since the resistivity isnt a number I wouldnt get a solution to then divide by .3631681108

OpenStudy (ankit042):

sorry it will not be .034. You have to convert meters to cm You know how to convert m to cm? so final answer 40*.3631681108/3.4*100

OpenStudy (anonymous):

Oh okay so ressitivity is .0427256601

OpenStudy (anonymous):

Thanks so much!!

OpenStudy (ankit042):

np :) You knew the concept...just make sure you put the right units. sometimes in physics you have to convert

OpenStudy (anonymous):

How many electrons pass a given point in the circuit in 19 min? The fundamental charge is 1.602 × 10−19 C. The current in a resistor decreases by 2.36 A when the voltage applied across the resistor decreases from 17.7 V to 6.44 V . Find the resistance of the resistor. Answer in units of Ω I'm confused on these two, what equations do I use ?

OpenStudy (anonymous):

@ankit042

OpenStudy (ankit042):

u have any idea how to proceed?

OpenStudy (anonymous):

Well I tried to determine this : (1.602 × 10^−19 C) (1.6 x 10^-19) then I divided that by 19

OpenStudy (anonymous):

the secnod one I didn't know how to approach it since there are to V's

OpenStudy (ankit042):

so it talks about change in voltage and change in current. Now as resistance remains constant you can use delta(v) = delta(I)*R

OpenStudy (anonymous):

This is for the second right?

OpenStudy (ankit042):

right

OpenStudy (anonymous):

So is it delta 17.7 x delta 6.44= delta 2.36 x R or is this completely wrong?

OpenStudy (ankit042):

delta(v) = 6.44-17.7 delta(I) = -2.36

OpenStudy (anonymous):

So R=4.771186441

OpenStudy (anonymous):

Now for the first one is there an equation for that?

OpenStudy (ankit042):

Do we know thr current passing in the circuit?

OpenStudy (anonymous):

I don't think so unless thats the same as the fundamental charge

OpenStudy (anonymous):

How many electrons pass a given point in the circuit in 19 min? The fundamental charge is 1.602 × 10−19 C.

OpenStudy (anonymous):

Do I divide 1.602 × 10^−19 C by 19

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