Question

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Answer 1

You can use the formula y = Vi * t + 0.5 * a * t^2, where:
y = Vertical displacement
Vi = Initial velocity = 15m/s
t = Time elapsed = 16s
a = Acceleration = g = -9.8m/s^2

y = 15 * 16 + 0.5 * -9.8m/s^2 * 16^2
y = 240m - 1254.4m = -1014.4m

Therefore, the package falls from a height of 1014.4m above the ground.

Answer 2

I found 1000 m??

Answer 3

when the package is dropped, it goes up and falls back. It takes 3.06 seconds to first place where it is dropped.

So, time elapsed is 16-3.06=12.94 seconds..

Y=12.94*15 + 0.5*9,8*12.94^2

Y=1014.5 meters