Using the given zero, find all other zeros of f(x). -2i is a zero of f(x) = x4 - 45x2 - 196
Answers 2i, 14i, -14i 2i, 7, -7 2i, 14, -14 2i, 7i, -7i
Well, complex roots always come in pairs. If you have (x-i), then you have to (x+i). That being said, you x = -2i, which meansing (x+2i) is one of the factors. Since you need a pair, this means that (x-2i) is also a factor. From here, there are several ways you can go about it really. If it works out, I think this is the easiet route: Knowing that (x-2i) and (x+2i) are factors, we can multiply it out and see what we get. Foiling this, I would get x^2 + 4 (feel free to ask if you want to see how I got that) Now that I have x^2 + 4, its possible to try and find the other factors by polynomial long division. I would do this division: \[\frac{ x ^{4}-45x ^{2}-196 }{ x ^{2}+4 } \]So now I can work out that long division: |dw:1379134621025:dw| Okay, awesome, we came up with x^2-49. Now this is a difference of squares that can be factored into (x+7)(x-7) *again, ask if you want to see how*. So this means our 4 roots in total are 2i, -2i, 7, -7.
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