Question

passing through (-2, 9/4), vertx at (4, 0).. find the equation of ellipse.. center @ origin..

Answer 1

what

Answer 2

let the eq. of ellipse be : \[\frac{x^{2}}{a^{2}}+\frac{y^{2}}{b^{2}}=1\],a>b

Answer 3

yes i substituted the points on the equation and viola.. stuck up

Answer 4

therefore a=4.

Now since (-2,9/4) lies on it ,therefore,
\[\frac{(-2)^{2}}{4^{2}}+\frac{(9/4)^{2}}{b^{2}}=1\]
find b.

Answer 5

okay wait

Answer 6

its 3 square root 3 / 2

Answer 7

a= 4?

Answer 8

yes since distance between center and vertex is a ,so a=4.

and you'll get b^2 = 27/4

Answer 9

yes!! finally thank you

Answer 10

:)