Calculus1
18 Online
OpenStudy (anonymous):
Lim sinx/x = 0 ?
x--> -Infiniti
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Can you use l'Hospital's rule?
OpenStudy (anonymous):
Nope , our teacher wants us to use only rules which we have studied yet
OpenStudy (anonymous):
Use squeeze theorem.
OpenStudy (anonymous):
Ok let me try
OpenStudy (anonymous):
It's a finite quantity divided by infinity, what do you think?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Oh i took the limit as x my mistake^^
OpenStudy (anonymous):
Or maybe 1 and -1 felt really brave one day and gave negative infinity a run for its money.
OpenStudy (anonymous):
Here is a hint: \(-1 \leq \sin(x)\leq 1\)
OpenStudy (anonymous):
So its 0
OpenStudy (anonymous):
I got that far ,then divide by x and substitute
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Either its 0 or im retarded
OpenStudy (anonymous):
Please dont tell me its the second
OpenStudy (anonymous):
Okay, since \(x\) will be negative, when you divide by \(x\) the inequalities flip.
OpenStudy (anonymous):
But yes, it does go to \(0\).
OpenStudy (anonymous):
Dont you mean divide1 by x
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
You divide the entire inequality. All things are divided by \(x\).
OpenStudy (anonymous):
\[
\frac 1x \leq \frac{\sin(x)}x\leq -\frac 1x
\]