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The sum of the first n terms of an arithmetic sequence is n^(2)+6n, Find the nth term of the sequence. @Callisto
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Find the sum of n terms, and the sum of (n-1) terms using the formula. Then, find the nth term by subtracting the sum of (n-1) terms from the sum of n terms.
(a+l)n / 2 ?
Just use the formula given in the question.
oh
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[(n-1)^(2) + 6(n-1) ] - n^(2)+6n ??
What one has a greater value - sum of n terms or sum of (n-1) terms?
n^(2)+6n - [(n-1)^(2) + 6(n-1) ]
Yes, always (sum of n terms) - (sum of (n-1) terms) to find the nth term. If you do (sum of (n-1) terms) - (sum of n terms), then you need to multiply the answer by -1 to get the nth term.
ok, i understand now
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