evaluate this matrix
\[2\left[\begin{matrix}1 & 5 \\ 6 & 0\end{matrix}\right] - 5\left[\begin{matrix}6 & 2 \\ 1 & 8\end{matrix}\right]\]
hmm, is just a plain scalar multiplication, and then the product, a matrix addition
\(\large z\times\begin{bmatrix}a&b\\c&d \end{bmatrix} \implies \begin{bmatrix}z\times a&z\times b\\z\times c&z\times d \end{bmatrix}\)
okay so i find the answer for both of the matrices and then do i multiply them both together or subtract them?
I think what you got to do first is to multiply the numbers in the matrixes by two then the other group by five. Then you subtract the numbers in the order of the placing in the matrixes to solve the problem.
yes \(\large \begin{bmatrix}a&b\\c&d\end{bmatrix} + \begin{bmatrix}e&f\\g&h \end{bmatrix} \implies \begin{bmatrix}a+e&b+f\\c+g&d+h \end{bmatrix}\)
pretty straightforward really
why are you adding them together if it's a subtraction sign. are you changing -5 to 5 and then adding or what?
well... ok... then just change that for a " - " :) same procedure
\(\large \begin{bmatrix}a&b\\c&d\end{bmatrix} - \begin{bmatrix}e&f\\g&h \end{bmatrix} \implies \begin{bmatrix}a-e&b-f\\c-g&d-h \end{bmatrix}\)
but that's all there's to it, just a scalar multiplication and "addition" or subtraction for that matter
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