Question

What is the approximate area of the composite figure shown? Use three point one four for pi.

Answer 1

help pls

Answer 2

HELP

Answer 3

the area of a square is A = b*h and the area of a semicircle is A = pi*r^2/2 so the area of the composite figure is A = b*h+pi*r^2/2

Answer 4

not a square a rectangle*

Answer 5

of wait so do i find the area of both the shapes then i add them up?

Answer 6

yeah

Answer 7

ok can you tell me formula for circle

Answer 8

ok so 240+

Answer 9

its more like 290-something

Answer 10

what???
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Answer 11

hmm, HELPMEWITHMYQUESTION what would be the area for the "rectangular" part of it only?

Answer 12

i got 12*20=240 then i add 240 with area of half a circle right?

Answer 13

jdoe im saying the rectangle would be 240

Answer 14

12*20+pi/2*6

Answer 15

ok... and now about the semi-circle on the right
what would be its "radius"?

Answer 16

6 would e radies

Answer 17

ok so now wat?

Answer 18

so 3.14*6^2

Answer 19

so 6 is the radius, let's get is Area then, area of a circle \(\large \boldsymbol{\pi r^2}\)

Answer 20

ohh... yes. 3.14. * 6^2... well, HALF-THAT is the area of the SEMI-circle

Answer 21

semi = half

Answer 22

i got 113.04 if i did 3.14*6^2

Answer 23

so now i divide 113.04/2?

Answer 24

yeap, because 113.04 is the Area of the whole circle, but the "figure" is only using half a circle, so half its Area only

Answer 25

when i do that i get 56.52

Answer 26

now i add 240+56?

Answer 27

ok, that's the Area of the "semi-circular" part, add that to the "rectangular" part and that sum will be the Area of the figure :)

Answer 28

ok wait

Answer 29

296?

Answer 30

around 296*

Answer 31

yeap

Answer 32

i gace u meadal for helping me thx man

Answer 33

yw

Answer 34

what