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Mathematics 11 Online
OpenStudy (katherinesmith):

Is the following system consistent or inconsistent?

OpenStudy (katherinesmith):

8x + y + 4 = 0 y = -8x - 4

ganeshie8 (ganeshie8):

it is consistent, if it has atleast one solution

OpenStudy (katherinesmith):

so do i just plug the y in and try to solve it?

ganeshie8 (ganeshie8):

find out how many solutions it can have, by watever method u want :)

OpenStudy (katherinesmith):

i got 0 = 0... what the heck does that mean

ganeshie8 (ganeshie8):

left side = right side that means, infinite solutions !

ganeshie8 (ganeshie8):

both equations are one and same !!

OpenStudy (katherinesmith):

how do i solve one like this: -2x - 2y = 6 10x + 10y = -30

ganeshie8 (ganeshie8):

simplify the equations first

OpenStudy (katherinesmith):

i'm really bad at that when there's a coefficient higher than 1 in front of the variables

ganeshie8 (ganeshie8):

so, make the coefficient 1 :) divide -2 in first equation divide 10 in second equation

ganeshie8 (ganeshie8):

first equation :- -2x - 2y = 6 divide -2 both sides -2x - 2y = 6 /-2 /-2 x + y = -3 -----------(1)

OpenStudy (katherinesmith):

x + y = -3 x + y = -3

OpenStudy (katherinesmith):

one of them is x - y = -3*****

ganeshie8 (ganeshie8):

both are x+y = -3

OpenStudy (katherinesmith):

okay so now what

ganeshie8 (ganeshie8):

that means both are same equations eh ?

OpenStudy (katherinesmith):

so no solution?

ganeshie8 (ganeshie8):

so, infinite solutions

OpenStudy (katherinesmith):

oohhh

ganeshie8 (ganeshie8):

if u solve them, u wud get 0 = 0

OpenStudy (katherinesmith):

i have one last question. what do i do for one that is like 2y = x - 7 -2x - 6y = -14

ganeshie8 (ganeshie8):

solve it and see

OpenStudy (katherinesmith):

2y = x - 7 x + 3y = 7

OpenStudy (katherinesmith):

now what

ganeshie8 (ganeshie8):

solve them

OpenStudy (katherinesmith):

how..

ganeshie8 (ganeshie8):

2y = x - 7 x + 3y = 7

ganeshie8 (ganeshie8):

solve y from first equation, and substitute it in second equation

OpenStudy (katherinesmith):

i don't know how i'm supposed to divide 2 into that entire first equation and then try and solve it.

OpenStudy (katherinesmith):

i'm gonna get weird numbers

ganeshie8 (ganeshie8):

you're on right track, do it :)

ganeshie8 (ganeshie8):

2y = x - 7 y = (x-7)/2

ganeshie8 (ganeshie8):

substitute this value for y in 2nd equation

OpenStudy (katherinesmith):

\[x + 3 = (\frac{ x }{ 2 } - \frac{ 7 }{ 2 } ) = 7\]

OpenStudy (katherinesmith):

i don't know how to do the rest.

ganeshie8 (ganeshie8):

u mean \(\large x + 3(\frac{ x }{ 2 } - \frac{ 7 }{ 2 } ) = 7 \) ?

ganeshie8 (ganeshie8):

u dont have to solve it completely, u can see it x will certainly have some value

ganeshie8 (ganeshie8):

so that means, the system will have ONE unique solution so the system is consistent

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