Write the expression in standard form.
3/(3-12i)

Question

Write the expression in standard form.
3/(3-12i)

anonymous · Answer

1/(1-4i)

ganeshie8 · Answer

$\large \frac{3}{3-12i}$

ganeshie8 · Answer

is it like above ? :)

anonymous · Answer

yes

anonymous · Answer

yes

anonymous · Answer

|dw:1379193220641:dw|

anonymous · Answer

the answer choices are -1/17 + 4/17i , 1/17-4/17i, -1/17-4/17i, and 1/17 + 4/17i

jdoe0001 · Answer

write it in standard form, in short means, get rid of the complex expression at the bottom

how? well, multiply top and bottom by the $\bf \text{conjugate}$ of the bottom

anonymous · Answer

I don't understand how to do that when it has complex zeros aka the i

anonymous · Answer

I see what you explained but I don't understand the relationship of that and the answer choices

anonymous · Answer

Would it be 1/17 - 4/17i?

ganeshie8 · Answer

complex conjugate of $3-12i$ is $3+12i$

jdoe is asking u to multiply top and bottom wid this

anonymous · Answer

ok

ganeshie8 · Answer

$\large \frac{3}{3-12i} $

$\large \frac{3}{3-12i} \times \frac{3+12i}{3+12i} $

anonymous · Answer

but how does multiplying the "i" work?

ganeshie8 · Answer

$\large \frac{3}{3-12i} $

$\large \frac{3}{3-12i} \times \frac{3+12i}{3+12i} $

$\large \frac{3(3+12i)}{(3-12i)(3+12i)} $

ganeshie8 · Answer

for now, i may use this :-
$\large (a+bi)(a-bi) = a^2+b^2$

ganeshie8 · Answer

*u/we

anonymous · Answer

ok

ganeshie8 · Answer

use that and simplify denominator

ganeshie8 · Answer

$\large \frac{3}{3-12i} $

$\large \frac{3}{3-12i} \times \frac{3+12i}{3+12i} $

$\large \frac{3(3+12i)}{(3-12i)(3+12i)} $

$\large \frac{3(3+12i)}{3^2+12^2} $

ganeshie8 · Answer

simplify completely

ganeshie8 · Answer

$\large \frac{3}{3-12i} $

$\large \frac{3}{3-12i} \times \frac{3+12i}{3+12i} $

$\large \frac{3(3+12i)}{(3-12i)(3+12i)} $

$\large \frac{3(3+12i)}{3^2+12^2} $

$\large \frac{3 \times 3(1+4i)}{153} $

anonymous · Answer

I got 1+2i/17 . It's supposed to be something else though.

ganeshie8 · Answer

$\large \frac{3}{3-12i} $

$\large \frac{3}{3-12i} \times \frac{3+12i}{3+12i} $

$\large \frac{3(3+12i)}{(3-12i)(3+12i)} $

$\large \frac{3(3+12i)}{3^2+12^2} $

$\large \frac{3 \times 3(1+4i)}{153} $

$\large \frac{9(1+4i)}{9 \times 17} $

anonymous · Answer

so 1/17 + 4/17i would be correct?

ganeshie8 · Answer

$\large \frac{3}{3-12i} $

$\large \frac{3}{3-12i} \times \frac{3+12i}{3+12i} $

$\large \frac{3(3+12i)}{(3-12i)(3+12i)} $

$\large \frac{3(3+12i)}{3^2+12^2} $

$\large \frac{3 \times 3(1+4i)}{153} $

$\large \frac{\cancel{9}(1+4i)}{\cancel{9} \times 17} $

$\large \frac{1+4i}{17} $

anonymous · Answer

yes, thank you again!

ganeshie8 · Answer

so 1/17 + 4/17i would be correct?

yup, wud be correct :)

ganeshie8 · Answer

np. you're wlcme  !