Question

help see in comments

Answer 1

\[2x^2-4x-1\]
using the quadratic formula i have
\[\frac{ 4\pm \sqrt{(-4)^2-4(2)(-1)} }{ 2(2) }\]
so then i get \[\frac{ 8\pm \sqrt{6} }{ 4 }\]

Answer 2

the answer says
\[\frac{ 2\pm \sqrt{6} }{ 2 }\]

Answer 3

\[
\sqrt{24}=2\sqrt{6}
\]

Answer 4

They just divided out that \(2\), that's all.

Answer 5

Your error was not having that \(2\).

Answer 6

Also your \(4\) became an \(8\).

Answer 7

ya because \[\sqrt{24}=\sqrt{2*2*2*3}\]
pull out the pair of 2's and get the six on the inside and 8 on outside

Answer 8

\[
4\pm\sqrt{24} = 4\pm 2\sqrt{6}\neq 8\pm \sqrt{6}
\]

Answer 9

The 2 doesn't belong to the 4.

Answer 10

makes sense got it