Question

Find the integrating factor and use it to find the general solution for the following differential equation: y'+1y = -(6+4t)

Answer 1

just apply formula. why is it hard?

Answer 2

dont know formula

Answer 3

in yours, which is P(t)?

Answer 4

i know p(t) is 1 and g(t) is -6-4t

Answer 5

but after that im lost

Answer 6

ok, so \(e^{\int p(t)}\) = ?

Answer 7

take step. \(\huge \int p(t)\) = ??

Answer 8

do it, answer me, just this time, you can do whatever you want

Answer 9

why??? you know p (t ) = 1 and you don't know integral of 1 = ?

Answer 10

sorry i went away from the pc
(t)

Answer 11

I don't understand your answer, write it down completely, please

Answer 12

∫p(t) = t

Answer 13

so, \[\huge e^{\int p(t)}= e^t, right?\] now, \[\huge\color{red} {e^{-\int (p(t)}}=?\]

Answer 14

e^t

Answer 15

where is my - sign?

Answer 16

why? don't get what I mean? just put minus sign before t, that's it. Please, be patient. I am serious. I do the step not for fun

Answer 17

-te^t

Answer 18

oh ok i didnt realize that was a negative sign